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25 June, 11:15

The function f is given by f (x) = 3x^2+1. What is the average value of f over the closed interval [1,3]?

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  1. 25 June, 11:43
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    You can find the answer using the equation (f (b) - f (a)) / (b-a). For this problem, a=1 and b=3.

    Then, plug in the numbers and solve:

    [ (3 (3) ^2+1) - (3 (1) ^2+1) ] / (3-1)

    = (28-4) / 2

    =12
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