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24 October, 15:29

A college basketball player makes 5/6 of his free throws. Assuming free throws are independent, the probability that he makes it exactly three of his next four free throws is

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  1. 24 October, 15:40
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    5/6=.83 or 83%

    100%-83%=16.7%

    3/4=75%-16.7%=58.3%

    It will 58.3% probability to make it in the bucket.
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