In triangle ABC angle A = 45, a = 9, c = 11. Find angle C to the nearest tenth.

A. 30.2 degrees

B. 35.3 degrees

C. 59.8 degrees

D. 54.7 degrees

Question

Andres Petersen

Mathematics

6 October, 22:40

In triangle ABC angle A = 45, a = 9, c = 11. Find angle C to the nearest tenth.

A. 30.2 degrees

B. 35.3 degrees

C. 59.8 degrees

D. 54.7 degrees

+4

Answers (2)

Know the Answer?

Layla Case · Answer 1

Using the Law of Sines

a / sine A = c / sine C

9 / 0.70711 = 11 / sine C

sine C = 11 * 0.70711 / 9

sine C = 0.8642455556

Angle C = arc sine (0.8642455556)

arc sine (0.8642455556) = 59.796

answer is C

Kramer · Answer 2

I think it is B ...

In triangle ABC angle A = 45, a = 9, c = 11. Find angle C to the nearest tenth.A. 30.2 degreesB. 35.3 degreesC. 59.8 degreesD. 54.7 degrees

In triangle ABC angle A = 45, a = 9, c = 11. Find angle C to the nearest tenth.

A. 30.2 degrees

B. 35.3 degrees

C. 59.8 degrees

D. 54.7 degrees