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6 October, 22:40

In triangle ABC angle A = 45, a = 9, c = 11. Find angle C to the nearest tenth.

A. 30.2 degrees

B. 35.3 degrees

C. 59.8 degrees

D. 54.7 degrees

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Answers (2)
  1. 6 October, 23:00
    0
    Using the Law of Sines

    a / sine A = c / sine C

    9 / 0.70711 = 11 / sine C

    sine C = 11 * 0.70711 / 9

    sine C = 0.8642455556

    Angle C = arc sine (0.8642455556)

    arc sine (0.8642455556) = 59.796

    answer is C
  2. 6 October, 23:00
    0
    I think it is B ...
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