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28 January, 02:30

If x^2+2xy+y^2=8 find 3 (x+y) ^2

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  1. 28 January, 02:54
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    3 (x + y) ² = 8

    3 (x + y) (x + y) = 8

    3 (x² + xy + xy + y²) = 8

    3 (x² + 2xy + y²) = 8

    3 (x²) + 3 (2xy) + 3 (y²) = 8

    3x² + 6xy + 3y² = 8
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