Find the vertex V and the x-intercepts x^1 and x^2 of the quadratic function f (x) = 2x^2 - 8x.

Question

Andres Galloway

Mathematics

1 February, 05:04

Find the vertex V and the x-intercepts x^1 and x^2 of the quadratic function f (x) = 2x^2 - 8x.

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Answers (1)

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Cole Flynn · Answer 1

1) did you try desmos?

2) you have to factor it. 2x^2-8x, you can remove 2x from it so it becomes x^2-4 which is a differnce of sqaures and factors out to (x-4) (x+4) so x = = / - 4. then from there to find the vertex you can eye ball it in this one because the x intercepts are nice adn centered. the x value of the vertex is going to be 0 because is right in between the x intercepts. then to find the y value, just put 0 into the eqation.