Suppose there are two types of tickets to a show: advance and same day. The combined cost of one advance ticket and one same day ticket is $60. For one performance, 20 advance tickets and 40 same day tickets were sold. The total amount paid for the tickets was $2000. What was the price of each kind of ticket?

Question

Ashley Fry

Mathematics

31 January, 22:39

Suppose there are two types of tickets to a show: advance and same day. The combined cost of one advance ticket and one same day ticket is $60. For one performance, 20 advance tickets and 40 same day tickets were sold. The total amount paid for the tickets was $2000. What was the price of each kind of ticket?

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Answers (1)

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Eliana Kirk · Answer 1

Answer = $30.00 advanced and $36.00 same day.

Step-by-step explanation: We can replace 20:40 ratio.

30 x 20 and 70 x 20 = 600 + 800 = 3/5 to find 2/4 = 12/20 finds 10/20 through HCF and hereafter we have one ticket is 1/6 more. So if 60 tickets were sold for 2000 then $33.33 would be the average and if one was 1/6 more than the other it is 0.5/6 higher than 33.33 = 2.66 more = £36 for All day and £30 for Advanced tickets. 36 x 20 = $600 and 36 x 40 = $1400. We know its $30 as we can double check its ratio after. 20:40 is 1/2 but then take off $3 each side to balance back to find $60 combined. $2000=1400+$600 = 1:2 and 2:4 ratio.