A jar contains 6 red jelly beans 4 green jellys beans and 4 blue jelly beans if we choose a jelly bean then another jelly bean without putting the first one back in the jar what is the probability that the first jelly bean will be blue and the second will be blue as well?

Question

Joe King

Mathematics

9 July, 21:04

A jar contains 6 red jelly beans 4 green jellys beans and 4 blue jelly beans if we choose a jelly bean then another jelly bean without putting the first one back in the jar what is the probability that the first jelly bean will be blue and the second will be blue as well?

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Answers (2)

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Grace Hill · Answer 1

It would be 3/13 because there is one less blue and one less sweet in the jar. originally the probability of blue would have been 4/14 and you didn't put it back so now its 3/13.

Marie Holloway · Answer 2

4/14 is the probability of drawing a blue jelly bean on the first draw.

And because we have one fewer jelly beans in total 14 - 1 = 13 and one fewer blue jelly beans 4 - 1 = 3.

3/13 is the probability of drawing a blue jelly bean on the second draw.