How far apart are the foci of an ellipse with a major axis of 10 feet and a minor axis of 6 feet?

Quadratic relations and comic sections unit test part 1

12. b. 8 feet

1. b ellipse

domain - 4<=x<=4

range - 3<=y<=3

2. c. x^2/3

3. c. 1/10 x^2

4. b. 5 inches

5. d. x=1/12 (y-4) ^2 + 2

6. b. (x-4) ^2 + (y-5) ^2 = 49

7. b. (x+8) ^2 + (y+4) ^2 = 25

8. d. (x+3) ^2 + (y+2) ^2 = 9

9. a. center at (7,-6); radius 4

10. b. x^2/25 + y^2/169 = 1

11. a. (0, + / - 6)

12. b. 8 ft

13. c. (put equation in graphing calculator to see graph)

14. d. (0, + / -5)

The focii are 8 feet apart

Step-by-step explanation:

You can use the formula

F = √ (a^2 - b^2) where F is the distance of the focii from the center, a = length of the semi major axis and b = length of the semi minor axis)

So here it is √ (5^2 - 3^2)

= √16 = 4

So the distance is 2*4 = 8