For the function d (x) = 7x^3 - 6x^2 what is the vaule of d (4)

For this case we have the following function:

d (x) = 7x ^ 3 - 6x ^ 2

We evaluate the function for x = 4.

We have then:

d (4) = 7 * (4) ^ 3 - 6 * (4) ^ 2

Rewriting we have:

d (4) = (4 ^ 2) * (7 * (4) - 6)

d (4) = 352

Answer:

the vaule of d (4) is:

d (4) = 352