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29 August, 03:27

The perimeter of a triangle is 117 inches. If one side of the triangle is four more than the shortest side, and the longest side is 11 more than the shortest side, find the lengths of the three sides?

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  1. 29 August, 04:05
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    A+b+c=117

    lets say that a is shortest and c is longest

    1 side is 4 more than shortest

    longest is 11 more than shortest

    now we know

    b=4+a (since longest is 11 more, this cannot be longest)

    c=11+a

    sub

    a+4+a+11+a=117

    add like terms

    3a+15=117

    minus 15 from both sides

    3a=102

    divide both sides by 3

    a=34

    find others

    b=4+a

    b=4+34

    b=38

    c=11+a

    c=11+34

    c=45

    the legnsh are

    34in, 38in, 45in
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