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11 December, 02:57

6x + 3y = 9

2x + 3y = 1

Solve the system of equations.

A) x = 2, y = - 1

B) x = - 1, y = 2

C) x = - 1/2, y = 3

D) x = 3, y = - 1/2

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Answers (2)
  1. 11 December, 03:04
    0
    Solution 1 ▶6 (x) + 3 (y) = 9

    Solution 2 ▶2 (x) + 3 (y) = 1

    Graphic organizer ▶3 (y) + 6 (x) = 9⬇

    3 (y) + 2 (x) = 1

    Solution 2⬇

    keep in mind the '2' becomes a negative!

    ▶3 (y) = - 2 (x) + 1

    ▶ (y) = - 2 (x) : 3 + 1 : 3

    Solution 1⬇

    x-intercept

    6 (x) + 3 (-2) (x) : 3+1:3) = 9

    ▶ 4 (x) = 8

    ▶4 (?) = 8

    ▶x = 2

    y-intercept⬇

    ▶ (y) = - 2 (x) : 3+1:3

    ▶ (y) = (-2:3) (2) + 1:3 = - 1

    ▶y = - 1

    x-intercept: 2

    y-intercept: - 1

    So, therefore your answer for this problem would have to be option A. x = 2, y = - 1
  2. 11 December, 03:24
    0
    6x + 3y = 9

    2x + 3y = 1

    subtracting both equation we get

    4x = 8 then

    x = 2 and putting the value of x in any one equation we get the value of y

    that is y = - 1

    options A is correct
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