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2 August, 13:00

Suppose that 29% of all residents of a community favor annexation by a nearby municipality. The probability that in a random sample of 50 residents at least 35% will favor annexation is

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  1. 2 August, 13:06
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    Let us say that,

    X = the number of residents in the sample who favor annexation.

    X has a distribution which follows a binomial curve with parameters:

    n=50 and p=0.29

    Calculating for mean:

    Mean of X = n * p = 50 * 0.29

    Mean of X = 14.5

    Calculating for standard deviation:

    Standard deviation of X = sqrt (n * p * (1 - p))

    Standard deviation of X = 3.2086

    Now we are to find the probability that at least 35% favour annexation:

    35% * 50 = 17.5 residents

    Normal approximation can be applied in this case since sample size is greater than 31. Therefore,

    Required Probability:

    P (X>=17.5) = 1 - P (X<17.5)

    1 - P (z< (17.5-14.5) / 3.2086) = 1 - P (z<0.9350) = 1 - 0.825106 = 0.174894

    Answer:

    0.175 or 17.5%
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