In the air, it had an average speed of 16 m/s/text{m/s}m/sm, slash, s. In the water, it had an average speed of 3 m/s/text{m/s}m/sm, slash, s before hitting the seabed. The total distance from the top of the cliff to the seabed is 127 meters, and the stone's entire fall took 12 seconds.

Question

Cannon Orozco

Mathematics

13 September, 16:53

In the air, it had an average speed of 16 m/s/text{m/s}m/sm, slash, s. In the water, it had an average speed of 3 m/s/text{m/s}m/sm, slash, s before hitting the seabed. The total distance from the top of the cliff to the seabed is 127 meters, and the stone's entire fall took 12 seconds.

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Answers (1)

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Beckett Strong · Answer 1

Need to specify the goal of this problem. I suspect that the goal is to specify how long the stone fell thru the air and then how long through the water.

Let t1 be the length of time the stone falls through air, and t2 through water.

The total time over which the stone falls is t1 + t2 = 12 seconds.

Since distance = (rate) times (time), 16t1 + 3t2=127 meters.

Solve this system of equations for t1 and t2.