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11 August, 02:03

What is the equation of a parabola with a directrix x = 8 and focus (-8,0)

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  1. 11 August, 02:26
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    From the given information, the parabola is a sideways parabola facing left with vertex at the origin.

    Required equation is (y - 0) ^2 = 4p (x - 0)

    y^2 = 4px

    But 0 + p = - 8 = > p = - 8

    Therefore, required equation is y^2 = 4 (-8) x

    y^2 = - 32x
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