The shortest side of a fight triangle measures20 m. The lengths of the other two sides are censecutive odd integers. Find the length of the two aides

A² + b² = c²

20² + n² = (n+2) ²

400 + n² = (n+2) (n+2)

400 + n²=n² + 2n + 2n + 4

400 + n² = n² + 4n + 4

400 + n²-n² = n²-n² + 4n+4

400 = 4n + 4

400-4 = 4n + 4-4

396 = 4n

396/4 = 4n/4

n = 99

20² + 99² = (99+2) ²

400 + 9801 = 10201

10201=10201