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E5 In (x + 1)

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  1. 29 May, 01:34
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    e^ (5 ln (x + 1)) = (x + 1) ^5

    Step-by-step explanation:

    e5 In (x + 1) or did you mean e^ (5 ln (x + 1))

    because then this would simplify a lot

    e^ (5 ln (x + 1)) = e ^ (ln (x + 1) ^5)

    e^ (5 ln (x + 1)) = e ^ (ln (x + 1) ^5) = (x + 1) ^5

    or did you mean (e^5) (ln (x + 1)) = ln [ (x+1) ^ (e^5) ]

    But I think you meant:

    e^ (5 ln (x + 1)) = e ^ (ln (x + 1) ^5) = (x + 1) ^5
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