Y varies directly with the square of X. If y = 5 when x=3, what is the value of y when x=9?

Question

Rangel

Mathematics

1 September, 02:54

Y varies directly with the square of X. If y = 5 when x=3, what is the value of y when x=9?

+1

Answers (1)

Know the Answer?

Elise · Answer 1

Answer:45

Step-by-step explanation:

y varies directly as x^2

y=k x x^2

When y=5 x=3

5=k x 3^2

5=k x 9

K=5/9

Relationship is y=5x^2/9

y = (5x9^2) ➗ 9

y = (5x81) ➗ 9

y=405 ➗ 9

y=45