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10 August, 12:07

What is the IQR (interquartile range) of the data set? 33, 37, 45, 61, 64, 67

A. 27

B. 37

C. 50.5

D. 64

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  1. 10 August, 12:30
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    solution is first os all find median

    median is (45+61) / 2=53

    find median of no in left of 53

    it is 37

    find median of no in right of 53

    it is 64

    now interquartile range=64-53=27
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