Complete the definition of the h (x) so that it is continuous over its domain.

h (x) = x^3, x<0

a, x=0

√x, 0 b, x=4

4 - 1/2x, x>4

a = b =

A=0

B=2

so we have our question, h (x) x^3, x<0.

a is equal to 0 since that answer was already given.

so now it would be srqt/x over 0 of 4

4 divided by 0 is 0

1/2x x>4

turns into 1/2x x>4/1

cross simplify

the answer to B is 2