Write the equation of a line that is perpendicular y=2/3x+9

To create a line that is perpendicular to the one given, completely invert the slope.

y = - 3/2x + 9

A line perpendicular to y=2/3x+9 would be y=-3/2x+k where k is any constant.

The slope of y=2/3x+9 is 2/3.

The negative reciprocal of 2/3 is - 3/2.

y=-3/2x+k where k is a constant.

k can be any constant, such as 2, 5, or even 65.

y=-3/2x+k would be the answer.