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6 November, 09:40

Determine the base length of a triangle that has an area if 48 inches

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  1. 6 November, 09:48
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    H=x and b=x+10

    A=hb/2 so

    A=x (x+10) / 2

    A = (x^2+10x) / 2 and A=48 so

    (x^2+10x) = 96

    x^2+10x-96-0

    x^2-6x+16x-96=0

    x (x-6) + 16 (x-6) = 0

    (x+16) (x-6) = 0, since x>0

    x=6in, and since the base is x+10

    base=16in
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