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14 September, 10:20

Mr. brown drove from his home to his school at the rate of 25 mph and returned by a different route at the rate of 30 mph. the route by which he returned was 5 miles longer than the route by which he went. the return trip took 10 minutes less than the trip out. find the distance mr. brown traveled each way.

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  1. 14 September, 10:33
    0
    If we let

    x and t1 as the distance traveled and the travel time, respectively using the first route

    y and t2 as the distance traveled and the travel time, respectively using the second route

    Then we have the equations:

    x = 25 t1

    y = 30 t2

    y = x + 5

    t2 = t1 - 10/60

    Solving of x, y, t1 and t2

    x = 50 mi

    y = 55 mi

    t1 = 2 hr

    t2 = 1.83 hr
  2. 14 September, 10:45
    0
    Hello there.

    Mr. brown drove from his home to his school at the rate of 25 mph and returned by a different route at the rate of 30 mph. the route by which he returned was 5 miles longer than the route by which he went. the return trip took 10 minutes less than the trip out. find the distance mr. brown traveled each way.

    1.83 hr
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