A resident in a particular city pays a water bil of $4 44 per montth plus $0.50 per 1000 galons of water used (up to 4000 galions) If this cty has 449,000 customers that use less than 4000 galons a month tnd its monthly revenue function R (), where the total number of gatons x is measured in thousands R (0) - (Use integers or decimals for any numbers in the expression Do not include the $ symbol in your answer)

Question

Annika

Mathematics

20 July, 16:19

A resident in a particular city pays a water bil of $4 44 per montth plus $0.50 per 1000 galons of water used (up to 4000 galions) If this cty has 449,000 customers that use less than 4000 galons a month tnd its monthly revenue function R (), where the total number of gatons x is measured in thousands R (0) - (Use integers or decimals for any numbers in the expression Do not include the $ symbol in your answer)

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Priscilla Frank · Answer 1

The total revenue is 1993560 + 0.5x

Step-by-step explanation:

Consider the provided information.

As we know Revenue = Fixed revenue + Variable revenue

A resident in a particular city pays a water bill of $4 44 per month plus $0.50 per 1000 gallons of water used.

Fixed revenue = Fixed charge * Number of customer

Fixed revenue = 4.44 * 449,000 = 1993560

Let x is the total number of gallons.

Variable revenue = 0.50 * x = 0.5x

Hence, the total revenue is 1993560 + 0.5x