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27 November, 08:47

a tour-bus operator sold $1,517 worth of tickets for a trip to Niagara Falls. Each tickets cost the same amount and could be paid for with three bills. What was the cost of a ticket

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  1. 27 November, 09:09
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    Tota tickets were sold = $1,517.

    Factoring 1517, we get ... 37 * 41 * 1 only.

    Because 37 and 41 are prime numbers, we can't factor it more.

    But we need to check if 41 or 37 would be cost of a ticket.

    To find this, we need to take Each tickets cost could be paid for with three bills.

    So, we need to divide 41 or 37 so that we can make it into three bills of integers numbers.

    We could choose integers numbers like 1, 5, 10, 20 ...

    We can take 20, 10, 7 that makes 37.

    So, cost of each ticket could be $37 and number of tickets could be 1517 divided by 37 gives 41 tickets.

    Other way, we could do,

    20, 20, 1 that makes 41.

    So, cost of each ticket could be $41 and number of tickets could be 1517 divided by 41 gives 37 tickets.

    We could either say: cost of each ticket = $41 and number of tickets = 37.

    Or cost of each ticket = $37 and number of tickets = 41.
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