What are the solutions to log6 (x squared + 8) = 1 + log6 (x)

x = - 2 and x = - -4

x = -1 and x = 8

x = 1 and x = -8

x = 2 and x = 4

Question

Beckham

Mathematics

20 November, 01:53

What are the solutions to log6 (x squared + 8) = 1 + log6 (x)

x = - 2 and x = - -4

x = -1 and x = 8

x = 1 and x = -8

x = 2 and x = 4

+4

Answers (1)

Know the Answer?

Valentino Walton · Answer 1

x = 2 and x = 4

Step-by-step explanation:

log6 (x squared + 8) = 1 + log6 (x)

log6 (x squared + 8) = log6 (6) + log6 (x)

log6 (x² + 8) = log6 (6x)

x² + 8 = 6x

x² - 6x + 8 = 0

x² - 4x - 2x + 8 = 0

x (x - 4) - 2 (x - 4) = 0

(x - 4) (x - 2) = 0

x = 2, 4

What are the solutions to log6 (x squared + 8) = 1 + log6 (x)x = - 2 and x = - -4x = -1 and x = 8x = 1 and x = -8x = 2 and x = 4

What are the solutions to log6 (x squared + 8) = 1 + log6 (x)

x = - 2 and x = - -4

x = -1 and x = 8

x = 1 and x = -8

x = 2 and x = 4