X^2+4x=0

Identify what the solution is and if it's no real solution or if it's 1 real solution or if it's 2real solution

Question

7 December, 09:09

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Answers (2)

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Bryanna Murphy · Answer 1

X^2+4x=0 factor out x

x (x+4) = 0

So there are two real solutions, when x=0 and - 4.

Jayla Gillespie · Answer 2

The correct answer to this question is x=0 and - 4

X^2+4x=0Identify what the solution is and if it's no real solution or if it's 1 real solution or if it's 2real solution