The power P of a jet of water is jointly proportional to the cross sectional area A and to the cube of the velocity v.

(a) the equation is P=kA (V) ^3

(b) If the velocity is doubled and the cross sectional area is tripled, by what factor will the power increase?

Question

7 December, 01:34

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Answers (1)

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Marie Abbott · Answer 1

Hello,

A: P=k*A*v^3

B:

v'=2v

A'=3A

P'=k*A'*V'^3

=k*3A * (2v) ^3=24*k*A*v^3

Factor=24

The power P of a jet of water is jointly proportional to the cross sectional area A and to the cube of the velocity v.(a) the equation is P=kA (V) ^3(b) If the velocity is doubled and the cross sectional area is tripled, by what factor will the power increase?