Ask Question
17 April, 20:29

What is the additive inverse of the complex number 13-2

+1
Answers (1)
  1. 17 April, 20:32
    0
    -13 + j*2

    Step-by-step explanation:

    The additive inverse of a complex number x = a + j*b

    is a number y, such that

    x + y = 0

    This means that

    y = - x = - a - j*b

    Therefore

    The additive inverse of 13 - j*2 is equal to

    - (13 - j*2) = - 13 + j*2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What is the additive inverse of the complex number 13-2 ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers