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15 February, 03:07

What is the answer to (8x+5) ^2=63? I've been stuck on this problem for about 10 minutes now.

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  1. 15 February, 03:19
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    When the equation is squared, you have to foil (8x+5), so it becomes

    (8x+5) (8x+5) = 63

    then you use the distributive property, so it become 64x^2 + 40x + 40x + 25, and you simplify that into 64x^2+80x+25=63

    next you subtract 63 from the left, sso it becomes 64x^2+80x-38=0

    then you use the quadratic formula - b + / - (root b^2-4ac) / 2a to solve for the zeros or x-values
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