Which function below is the inverse of f (x) = x^2-36

X^2/36

+ - 6 square root of x

1/x^2-36

+ - square root of x+36

Question

Guest

Mathematics

13 November, 14:07

Which function below is the inverse of f (x) = x^2-36

X^2/36

+ - 6 square root of x

1/x^2-36

+ - square root of x+36

+5

Answers (1)

Know the Answer?

Odie · Answer 1

+ - square root of x+36

Step-by-step explanation:

f (x) = x^2 - 36

y = x^2 - 36

Exchange x and y

x = y^2 - 36

Solve for y

Add 36 to each side

x+36 = y^2 - 36+36

x+36 = y^2

Take the square root of each side

±sqrt (x+36) = y

±sqrt (x+36) = f^-1 (x)

Which function below is the inverse of f (x) = x^2-36X^2/36+ - 6 square root of x1/x^2-36+ - square root of x+36

Which function below is the inverse of f (x) = x^2-36

X^2/36

+ - 6 square root of x

1/x^2-36

+ - square root of x+36