Jana hit a golf ball with an initial velocity of 102 ft per second at an angle of 67 degrees with the horizontal. After 2 second how far had the ball traveled horizontally? after 3 seconds how far has the ball traveled vertically?

Question

Charlize Payne

Mathematics

4 April, 23:22

Jana hit a golf ball with an initial velocity of 102 ft per second at an angle of 67 degrees with the horizontal. After 2 second how far had the ball traveled horizontally? after 3 seconds how far has the ball traveled vertically?

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Answers (1)

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Lindsay Gonzales · Answer 1

Horizontal distance x (t) = ut cos θ

x (2) = 102 * 2 * cos 67 = 79.7 ft.

Vertical distance y (t) = ut sin θ - 1/2 gt^2

y (3) = 102 * 2 * sin 67 - 1/2 * 9.8 * (3) ^2 = 187.78 - 44.1 = 143.7 ft.