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23 May, 21:25

The area of the rectangle is 50 yd2. What is the formula that shows the length of side y?

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  1. 23 May, 21:48
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    Let L = lengthLet W = width Length is 5 yd less than twice the width = = > L = 2*W - 5 Area is 52 yd^2 = = > 52 = L*W Substitute the value for L from the 1st equation into the 2nd equation

    52 = (2*W - 5) * W52 = 2*W^2 - 5*W0 = 2*W^2 - 5*W - 52 0 = (2W - 13) * (W + 4) 2W - 13 = 0 or W + 4 = 0W = 13/2 or W = - 4 Width cannot be negative so discard W = - 4 W = 13/2 = = > L = 2 * (13/2) - 5 = 13 - 5 = 8 So the width is 13/2 yards and the length is 8 yards Check: 2 * (13/2) - 5 = 13 - 5 = 8 (13/2) * 8 = 4*13 = 52 yd^2
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