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13 May, 04:57

In a random sample of 60 computers, the mean repair cost was

$150with a population standard deviation of $36. Construct a

99%confidence interval for the population mean.

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  1. 13 May, 05:12
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    Step-by-step explanation:

    We want to construct a 99% confidence interval for the population mean

    Number of sample, n = 60

    Mean, u = $150

    Standard deviation, s = $36

    For a confidence level of 99%, the corresponding z value is 2.58. This is determined from the normal distribution table.

    We will apply the formula

    Confidence interval

    = mean + / - z * standard deviation/√n

    It becomes

    150 ± 2.58 * 36/√60

    = 150 ± 2.58 * 4.65

    = 150 ± 11.997

    The lower end of the confidence interval is 150 - 11.997 = 138.003

    The upper end of the confidence interval is 150 + 11.997 = 161.997

    Therefore, with 99% confidence interval, the population mean is between $138.003 and $161.997
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