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17 April, 13:43

At a large local university, 40% of the students live in the dormitories. A random sample of 80 students is selected for a particular study. The probability that the sample proportion (the proportion living in the dormitories) is between 0.30 and 0.50 is what?

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  1. 17 April, 14:02
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    0.9325

    Step-by-step explanation:

    Given

    n = sample size = 80

    p = probability = 0.4

    q = 1 - p = 0 ... 6

    standard deviation for the proportion = √ (p * q) / n = √ (0.4*0.6) / 80 = 0.0547

    for the proportion mean is 0.4

    now we can find z and the probability

    P (0.3
    P (0.3
    Using a z table

    P (0.3
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