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12 September, 09:00

What is the remainder when the polynomial 8x^2 + 4-3 is divided by 2x-1

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  1. 12 September, 09:11
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    To find the remainder, we can use the remainder theorem.

    To do this, first we need to set 2x - 1 equal to 0.

    2x - 1 = 0

    Solve for x.

    2x = 1

    x = 1/2

    Now that we have this value, we can solve for the remainder of this polynomial by replacing each x value with 1/2.

    8 (1/2) ^2 + 4 (1/2) - 3 = 1

    The remainder is 1.
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