Giorgio surveyed 45 randomly selected shoppers at the mall and found that approximately 24% believe that the food court needs to be remodeled. To the nearest percent, with a confidence level of 99% (z-score 2.58), what is the confidence interval for the proportion of shoppers who believe the food court needs to be remodeled? E = z and C = + E

Question

Celia Ramos

Mathematics

20 March, 22:16

Giorgio surveyed 45 randomly selected shoppers at the mall and found that approximately 24% believe that the food court needs to be remodeled. To the nearest percent, with a confidence level of 99% (z-score 2.58), what is the confidence interval for the proportion of shoppers who believe the food court needs to be remodeled? E = z and C = + E

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Ismael Kerr · Answer 1

We have N = 45 and P =.24. A confidence level is given by (45) (.24) - 2.58 (sigma/sqrt (45)). We are not given the standard deviation so without that, we would have to use the critical value of t, but it is not given in this problem.