A rectangular lot is 60 yards wide and 110 yards long. give the length and width of another rectangular lot that has the same perimeter but a smaller area.

P = 2 (L + W)

P = 2 (110 + 60)

P = 2 (170)

P = 340

A = L * W

A = 110 * 60

A = 6600

so the perimeter is 340 and the area is 6600

same pyramid, smaller area ...

L = 120

W = 50

P = 2 (120 + 50)

P = 2 (170)

P = 340 ... same perimeter

A = L * W

A = 120 * 50

A = 6000 ... smaller area

so the other rectangle can have a length of 120 yds and a width of 50 yds to have the same perimeter and a smaller area