6. Jack is building a rectangular dog pen that he wishes to enclose. The width of the pen is 2

yards less than the length. If the area of the pen is 15 square yards, how many yards of

fencing would he need to completely enclose the pen?

Let L=length

Let witz

L-2

A = 15 (lxw)

Question

Jerimiah Kim

Mathematics

10 November, 05:07

6. Jack is building a rectangular dog pen that he wishes to enclose. The width of the pen is 2

yards less than the length. If the area of the pen is 15 square yards, how many yards of

fencing would he need to completely enclose the pen?

Let L=length

Let witz

L-2

A = 15 (lxw)

+4

Answers (1)

Know the Answer?

Parker Liu · Answer 1

Pretty sure the width is 3 and the length is 5.

Step-by-step explanation:

What are the multiples of 15 (3 and 5) those are the only multiples besides 1 and 15. If that makes sense.

6. Jack is building a rectangular dog pen that he wishes to enclose. The width of the pen is 2yards less than the length. If the area of the pen is 15 square yards, how many yards offencing would he need to completely enclose the pen?Let L=lengthLet witzL-2A = 15 (lxw)

6. Jack is building a rectangular dog pen that he wishes to enclose. The width of the pen is 2

yards less than the length. If the area of the pen is 15 square yards, how many yards of

fencing would he need to completely enclose the pen?

Let L=length

Let witz

L-2

A = 15 (lxw)