The lengths of a particular snake are approximately normally distributed with a given mean Mu = 15 in. and standard deviation Sigma = 0.8 in. What percentage of the snakes are longer than 16.6 in.? 0.3% 2.5% 3.5% 5%

Question

Eddie May

Mathematics

19 February, 16:22

The lengths of a particular snake are approximately normally distributed with a given mean Mu = 15 in. and standard deviation Sigma = 0.8 in. What percentage of the snakes are longer than 16.6 in.? 0.3% 2.5% 3.5% 5%

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Answers (1)

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Macey Trevino · Answer 1

Answer: 5%

Step-by-step explanation:

Let see that the snakes that are longer than 16.6 in are lomger than mean at 16.6-15=1.6 in

1.6:Sigma=1.6: 0.8=2 that means that all other snakes but longer than 16.6 in are inside + -2 Sigma. It is known that for normal distribution 95.4% of all snakes are inside + -2 Sigma

That means that 100%-95.4%=4.6% or about 5% of the snakes are longer than 16.6 in