Solve the quadratic equation 4v^2-10v-22=0

4v^2-10v-22=0

a b c

x = - b + / - square root of b^2 - 4ac all divide by 2a

x = - (-10) + / - square root of - 10^2 - 4 (4) (-22) all divided by 2 (4)

x = 10 + / - square root of 100+352 all divided by 8

x = 10 + / - square root of 452 all divided by 8

x = 10 + / - 21 divided by8

4v² - 10v - 22 = 0

v = - (-10) + / - √ ((-10) ² - 4 (4) (-22))

2 (4)

v = 10 + / - √ (100 + 352)

8

v = 10 + / - √ (452)

8

v = 10 + / - 21.26

8

v = 1.25 + / - 2.66

v = 1.25 + 2.66 v = 1.25 - 2.66

v = 3.91 v = - 1.41