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Wang
Mathematics
25 April, 19:34
Solve the quadratic equation 4v^2-10v-22=0
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Gabriel Woodward
25 April, 19:44
0
4v^2-10v-22=0
a b c
x = - b + / - square root of b^2 - 4ac all divide by 2a
x = - (-10) + / - square root of - 10^2 - 4 (4) (-22) all divided by 2 (4)
x = 10 + / - square root of 100+352 all divided by 8
x = 10 + / - square root of 452 all divided by 8
x = 10 + / - 21 divided by8
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Elsa Marquez
25 April, 20:03
0
4v² - 10v - 22 = 0
v = - (-10) + / - √ ((-10) ² - 4 (4) (-22))
2 (4)
v = 10 + / - √ (100 + 352)
8
v = 10 + / - √ (452)
8
v = 10 + / - 21.26
8
v = 1.25 + / - 2.66
v = 1.25 + 2.66 v = 1.25 - 2.66
v = 3.91 v = - 1.41
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