on Wednesday, an aquarium at a pet store contained 230 pink fish, 310 blue fish, and 110 yellow fish. On Thursday, 37 yellow fish and 48 pink fish were sold. How many blue fish must be sold on Friday so that the combined population of pink fish and yellow fish will be five-sevenths the total population by the close of business on Friday, if no pink and yellow fish will be sold on Friday?

Question

Jaydon Cabrera

Mathematics

13 April, 10:52

on Wednesday, an aquarium at a pet store contained 230 pink fish, 310 blue fish, and 110 yellow fish. On Thursday, 37 yellow fish and 48 pink fish were sold. How many blue fish must be sold on Friday so that the combined population of pink fish and yellow fish will be five-sevenths the total population by the close of business on Friday, if no pink and yellow fish will be sold on Friday?

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Leslie Graham · Answer 1

add up the total amount of fish there are all together at the initial date that would be 650 now add up 37 and 48 which is 85, now subtract that from 650 you will get 565 now multiply 5/7 by 650 to get 464 then subtract 464 from 565 to get 101 that's how many fish would need to be sold for there to be 5/7 of the store sold