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5 July, 13:00

I need 2 cones with different dimensions but the same volume

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  1. 5 July, 13:02
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    Cone Volume = (π • r² • h) : 3

    radius = 4

    height = 24

    Cone Volume = (PI * 4*4*24) / 3

    Cone Volume = 402.12

    If we reduce the height by 4 (from 24 to 6) then we have to increase the radius by 2 (from 4 to 8) because the radius is squared.

    Cone Volume = (PI * 8*8*6) / 3

    Cone Volume = 402.12
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