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Hadley Oneill
Mathematics
7 April, 07:23
Find cscx if sinx+cotx cosx = sqrt3
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Kaylynn Marquez
7 April, 07:43
0
The answer is (d) ⇒ cscx = √3
Step-by-step explanation:
∵ sinx + (cotx) (cosx) = √3
∵ sinx + (cosx/sinx) (cosx) = √3
∴ sinx + cos²x/sinx = √3
∵ cos²x = 1 - sin²x
∴ sinx + (1 - sin²x) / sinx = √3 ⇒ make L. C. M
∴ (sin²x + 1 - sin²x) / sinx = √3
∴ 1/sinx = √3
∵ 1/sinx = cscx
∴ cscx = √3
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