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Rachael Vargas
Mathematics
11 September, 20:57
How do you factorize p2 + 2p - 3 = 0
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Answers (
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Emery Cooke
11 September, 21:21
0
Solution
p = {-3, 1}
Step-by-step explanation:
Simplifying
p2 + 2p + - 3 = 0
Reorder the terms:
-3 + 2p + p2 = 0
Solving
-3 + 2p + p2 = 0
Solving for variable 'p'.
Factor a trinomial.
(-3 + - 1p) (1 + - 1p) = 0
Subproblem 1
Set the factor ' (-3 + - 1p) ' equal to zero and attempt to solve:
Simplifying
-3 + - 1p = 0
Solving
-3 + - 1p = 0
Move all terms containing p to the left, all other terms to the right.
Add '3' to each side of the equation.
-3 + 3 + - 1p = 0 + 3
Combine like terms: - 3 + 3 = 0
0 + - 1p = 0 + 3
-1p = 0 + 3
Combine like terms: 0 + 3 = 3
-1p = 3
Divide each side by '-1'.
p = - 3
Simplifying
p = - 3
Subproblem 2
Set the factor ' (1 + - 1p) ' equal to zero and attempt to solve:
Simplifying
1 + - 1p = 0
Solving
1 + - 1p = 0
Move all terms containing p to the left, all other terms to the right.
Add '-1' to each side of the equation.
1 + - 1 + - 1p = 0 + - 1
Combine like terms: 1 + - 1 = 0
0 + - 1p = 0 + - 1
-1p = 0 + - 1
Combine like terms: 0 + - 1 = - 1
-1p = - 1
Divide each side by '-1'.
p = 1
Simplifying
p = 1
Solution
p = {-3, 1}
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