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21 August, 17:35

in a gambling game, for every play, there is a 0.1 probability that you win $7 and a 0.9 probability that you lose $1. What is the expected value of this game?

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  1. 21 August, 17:58
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    Answer:The expected value of this gambling game = $ 0.2

    Step-by-step explanation:

    The probability of winning $ 7 = 0.1

    The probability of losing $ 1 = 0.9

    The expected value of this game = total probability of winning and losing

    = 0.1 (7) + 0.9 (-1)

    [ - 1 indicates losing and so negative sign ]

    = 0.7 - 0.9

    = - 0.2

    = $ 0.2
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