The axis of symmetry for the graph of the function is f (x) = 1/4 x2 bx 10 is x = 6. what is the value of b?

F (x) = 1/4 x^2 + bx + 10 = 1/4 (x^2 + 4bx + 40) = 1/4 (x^2 + 4bx + 4b^2 + 40 - 4b^2) = 1/4 (x + 2b) ^2 + 1/4 (40 - 4b^2) = 1/4 (x + 2b) ^2 + 10 - b^2

Axis of symmetry is x = 6 implies that 2b = 6

Therefore, b = 6/2 = 3