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10 November, 05:55

Given f (x) = x2+8x+13 . Enter the quadratic function in vertex form in the box. f (x) =

+3
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  1. 10 November, 06:12
    0
    The vertex form of this equation is f (x) = (x + 4) ^2 - 3

    In order to change an equation from standard form to vertex form, you must use a process called completing the square. To use this follow the steps below.

    f (x) = x^2 + 8x + 13

    Start by subtracting the constant from both sides.

    f (x) - 13 = x^2 + 8x

    Now take half of the coefficient of the x term and square it. Since the x term has a coefficient of 8, we take half of it (4) and square it (16). Now we add that to both sides.

    f (x) - 13 + 16 = x^2 + 8x + 16

    f (x) + 3 = x^2 + 8x + 16

    Now that you've done these two steps, you can factor the right side into a perfect square.

    f (x) + 3 = (x + 4) ^2

    And then we subtract the new constant from both sides.

    f (x) = (x + 4) ^2 - 3
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