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3 December, 20:36

What are the zeros of the function?

h (x) = x3-2x2-3x

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  1. 3 December, 20:43
    0
    X=0, 3, - 1

    Factor out the x in the function, so you get x (x^2-2x-3). Then, factor the quadratic, getting x (x-3) (x+1). Set each part equal to 0.
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