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30 November, 23:24

Suppose the average golfer drives the ball around 214.33 yards with a standard deviation of 6.73. However, when given a new type of driver, every observation in the dataset is multiplied by 1.26. What is the new standard deviation?

a. 204.27

b. 10.81

c. 255.79

d. 9.84

e. 8.58

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  1. 30 November, 23:39
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    Therefore, a new standard deviation is 8.58.

    Step-by-step explanation:

    We know that the average golfer drives the ball around 214.33 yards with a standard deviation of 6.73.

    We calculate the percentage deviation, and we get

    214.33 : 100%=6.73 : x%

    214.33x=100·6.73

    214.33x=673

    x=673/214.33

    x=3.1400177%

    We calcualte a new type. We get that now golfer drives the ball

    214.33· 1.26=270.0558

    Now, we calculate a new standard deviation:

    270.05558 : 100%=x : 3.1400177%

    100x=270.05558 · 3.1400177

    100x = 847.99

    x=847.99/100

    x=8.48 ≈ 8.58

    Therefore, a new standard deviation is 8.58.
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