If 6 pears and 5 oranges cost $1.87 and 12 pears and 2 oranges cost $1.90, how much would 3 pears and 3 oranges cost?

I'm going to do elimination to find the price of one pear and one orange.

6p + 5o = 1.87

12p + 2o=1.90

I'm going to multiply the first equation by - 2.

-12p-10o = - 3.74

12p + 2o = 1.90

-8o = - 1.84

-1.84: - 8 =.23 = o

12p + 2 (.23) = 1.90

12p +.46 = 1.90

12p = 1.44

p=.12

A pear equals. 12, while an orange equals. 23.

3*.12 =.36

.23 * 3 =.69

.69 +.36 = 1.05

It would cost $1.05.